4.9x^2+4.9x-300=0

Solution for 4.9x^2+4.9x-300=0 equation:

4.9x^2+4.9x-300=0

a = 4.9; b = 4.9; c = -300;
Δ = b2-4ac
Δ = 4.92-4·4.9·(-300)
Δ = 5904.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.9)-\sqrt{5904.01}}{2*4.9}=\frac{-4.9-\sqrt{5904.01}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.9)+\sqrt{5904.01}}{2*4.9}=\frac{-4.9+\sqrt{5904.01}}{9.8}
$